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Feb 23, 2021 at 2:57 vote accept Chris Schmitz
Feb 22, 2021 at 19:48 answer added Edgar Bonet timeline score: 1
Feb 22, 2021 at 17:31 comment added Chris Schmitz @Juraj those are the message formats that the library I'm using gives me. There's not an option for just a buffer of bytes. I would think that the c-string is the equivalent of the buffer, but there's the null terminator issue.
Feb 22, 2021 at 17:27 comment added Juraj it looks like a X->Y problem. "I'm getting a message from a server that comes through as either a c style string, a standard library string, or a WString" why?
Feb 22, 2021 at 17:03 comment added dandavis might have to hex encode the values to transmit them.
Feb 22, 2021 at 16:52 review Close votes
Mar 10, 2021 at 3:04
Feb 22, 2021 at 16:23 comment added timemage Well, "c-string" basically means zero or more non-'\0' followed by '\0'. If any of your numbers happen to have a zero byte in them, that will terminate the "string" before the end of your actual data. E.g. 0xAA00BB. It's really just not a string at all. In terms of how you get the data out of it, if it's properly aligned for uint32_t, you can just const uint32_t *ui32p = reinterpret_cast<const uint32_t *>(mycharptr); If it's not aligned, you would do something like memcpy it into an array or individual elements into a single uint32_t variable. There's nothing really "Arduino" here.
Feb 22, 2021 at 16:16 comment added Chris Schmitz but yeah, data is a c-string of bytes and I know that I want to interpret it as 32 bit integers, I just can't figure out how to do it.
Feb 22, 2021 at 16:15 comment added Chris Schmitz Oh, I just mean data (the const char *) holds bits in it that can't be Serial.println-ed because because even in 8 bit form they're not ascii/utf valid characters so nothing goes to the monitor.
Feb 22, 2021 at 15:47 comment added timemage "they're just bit values". You mean, they're just uint32_t that are being pointed at with a const char * ?
Feb 22, 2021 at 15:36 history asked Chris Schmitz CC BY-SA 4.0