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No need for &15, rust does that under the hood

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edited Sep 7, 2015 at 18:52

Rust, 116111 bytes

More of a comment on @Doorknob's answer, but I don't have any rep for comments as I just created an account.

One can shave 510 bytes off his Rust solution with the following:

fn r(s:&str)->u8{let mut n=0u8;for t in s.chars(){n=match t{'!'=>!n,'>'=>n>>1,'<'=>n<<1,'@'=>n>>4|(n&15)<<4'@'=>n>>4|n<<4,_=>n}}n}

More of a comment on @Doorknob's answer, but I don't have any rep for comments as I just created an account.

One can shave 5 bytes off his Rust solution with the following:

fn r(s:&str)->u8{let mut n=0u8;for t in s.chars(){n=match t{'!'=>!n,'>'=>n>>1,'<'=>n<<1,'@'=>n>>4|(n&15)<<4,_=>n}}n}

More of a comment on @Doorknob's answer, but I don't have any rep for comments as I just created an account.

One can shave 10 bytes off his Rust solution with the following:

fn r(s:&str)->u8{let mut n=0u8;for t in s.chars(){n=match t{'!'=>!n,'>'=>n>>1,'<'=>n<<1,'@'=>n>>4|n<<4,_=>n}}n}

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answered Sep 7, 2015 at 18:40

user4867444

More of a comment on @Doorknob's answer, but I don't have any rep for comments as I just created an account.

One can shave 5 bytes off his Rust solution with the following:

fn r(s:&str)->u8{let mut n=0u8;for t in s.chars(){n=match t{'!'=>!n,'>'=>n>>1,'<'=>n<<1,'@'=>n>>4|(n&15)<<4,_=>n}}n}