Timeline for Identifying quad patterns in a two-dimensional array
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 20, 2013 at 10:02 | comment | added | Anko | @coding I'm happy it's of help. :) | |
| Feb 20, 2013 at 4:49 | comment | added | codinghands | Been working on this recently again - thanks once more for the great answer. | |
| Feb 20, 2013 at 4:49 | vote | accept | codinghands | ||
| Jan 25, 2013 at 17:48 | comment | added | codinghands | I will review when it is not 4am and report back! | |
| Jan 25, 2013 at 16:03 | comment | added | Anko | @coding I've edited the answer to cover rectangles, though in less depth. Is it intelligible? | |
| Jan 25, 2013 at 16:02 | history | edited | Anko | CC BY-SA 3.0 |
Updated with details on rectangular quad areas.
|
| Jan 25, 2013 at 12:00 | history | edited | Anko | CC BY-SA 3.0 |
Fixed equality typo. Oh yes, classic.
|
| Jan 25, 2013 at 11:59 | comment | added | Anko |
@coding Indeed, the inequality is a typo: I meant y <= yVariable < y+n! I'll fix that!
|
|
| Jan 25, 2013 at 11:44 | comment | added | codinghands | Okay, a couple of things after some manic doodling in my pad... is there any way to generalise this for any rectangle shape (3 x 5, 2 x 4)? Also, is there a special case where we're checking grid[0,0] for a 2x2 grid (i.e. n = 1), as yVariable must break the constraint y < yVariable < y+n (y being 0, y+n being 1). Or not even a special case actually - to confirm a quad at grid[0,0], we need to check [0,1] (bottom), [1,0] (right) and [1,1] (bottom right). So yVar must be 0, equalling y... Though my maths is awful :( | |
| Jan 25, 2013 at 11:11 | comment | added | codinghands | Thank you for the comprehensive answer! I need some time to work through it, no doubt have some daft follow up questions :) really appreciated! | |
| Jan 25, 2013 at 8:50 | history | answered | Anko | CC BY-SA 3.0 |
