This notebook was prepared by Donne Martin. Source and license info is on GitHub.
Challenge Notebook¶
Problem: Given a positive integer, get the next largest number and the next smallest number with the same number of 1's as the given number.¶
Constraints¶
- Is the output a positive int?
- Yes
- Can we assume the inputs are valid?
- No
- Can we assume this fits memory?
- Yes
Test Cases¶
- None -> Exception
- 0 -> Exception
- negative int -> Exception
- General case:
* Input: 0000 0000 1101 0111 * Next largest: 0000 0000 1101 1011 * Next smallest: 0000 0000 1100 1111
Algorithm¶
Refer to the Solution Notebook. If you are stuck and need a hint, the solution notebook's algorithm discussion might be a good place to start.
Code¶
In [ ]:
class Bits(object):
def get_next_largest(self, num):
# TODO: Implement me
pass
def get_next_smallest(self, num):
# TODO: Implement me
pass
Unit Test¶
The following unit test is expected to fail until you solve the challenge.
In [ ]:
# %load test_get_next_largest.py
import unittest
class TestBits(unittest.TestCase):
def test_get_next_largest(self):
bits = Bits()
self.assertRaises(Exception, bits.get_next_largest, None)
self.assertRaises(Exception, bits.get_next_largest, 0)
self.assertRaises(Exception, bits.get_next_largest, -1)
num = int('011010111', base=2)
expected = int('011011011', base=2)
self.assertEqual(bits.get_next_largest(num), expected)
print('Success: test_get_next_largest')
def test_get_next_smallest(self):
bits = Bits()
self.assertRaises(Exception, bits.get_next_smallest, None)
self.assertRaises(Exception, bits.get_next_smallest, 0)
self.assertRaises(Exception, bits.get_next_smallest, -1)
num = int('011010111', base=2)
expected = int('011001111', base=2)
self.assertEqual(bits.get_next_smallest(num), expected)
print('Success: test_get_next_smallest')
def main():
test = TestBits()
test.test_get_next_largest()
test.test_get_next_smallest()
if __name__ == '__main__':
main()
Solution Notebook¶
Review the Solution Notebook for a discussion on algorithms and code solutions.