This notebook was prepared by Donne Martin. Source and license info is on GitHub.
Challenge Notebook¶
Problem: Implement breadth-first search on a graph.¶
Constraints¶
- Is the graph directed?
- Yes
- Can we assume we already have Graph and Node classes?
- Yes
- Can we assume this is a connected graph?
- Yes
- Can we assume the inputs are valid?
- Yes
- Can we assume this fits memory?
- Yes
Test Cases¶
Input:
add_edge(source, destination, weight)
graph.add_edge(0, 1, 5)
graph.add_edge(0, 4, 3)
graph.add_edge(0, 5, 2)
graph.add_edge(1, 3, 5)
graph.add_edge(1, 4, 4)
graph.add_edge(2, 1, 6)
graph.add_edge(3, 2, 7)
graph.add_edge(3, 4, 8)
Result:
- Order of nodes visited: [0, 1, 4, 5, 3, 2]
Algorithm¶
Refer to the Solution Notebook. If you are stuck and need a hint, the solution notebook's algorithm discussion might be a good place to start.
Code¶
In [ ]:
%run ../graph/graph.py
In [ ]:
class GraphBfs(Graph):
def bfs(self, root, visit_func):
# TODO: Implement me
pass
Unit Test¶
The following unit test is expected to fail until you solve the challenge.
In [ ]:
%run ../utils/results.py
In [ ]:
# %load test_bfs.py
import unittest
class TestBfs(unittest.TestCase):
def __init__(self, *args, **kwargs):
super(TestBfs, self).__init__()
self.results = Results()
def test_bfs(self):
nodes = []
graph = GraphBfs()
for id in range(0, 6):
nodes.append(graph.add_node(id))
graph.add_edge(0, 1, 5)
graph.add_edge(0, 4, 3)
graph.add_edge(0, 5, 2)
graph.add_edge(1, 3, 5)
graph.add_edge(1, 4, 4)
graph.add_edge(2, 1, 6)
graph.add_edge(3, 2, 7)
graph.add_edge(3, 4, 8)
graph.bfs(nodes[0], self.results.add_result)
self.assertEqual(str(self.results), "[0, 1, 4, 5, 3, 2]")
print('Success: test_bfs')
def main():
test = TestBfs()
test.test_bfs()
if __name__ == '__main__':
main()
Solution Notebook¶
Review the Solution Notebook for a discussion on algorithms and code solutions.