This notebook was prepared by Donne Martin. Source and license info is on GitHub.
Challenge Notebook¶
Problem: Given a list of tuples representing ranges, condense the ranges.¶
Example: [(2, 3), (3, 5), (7, 9), (8, 10)] -> [(2, 5), (7, 10)]
Constraints¶
- Are the tuples in sorted order?
- No
- Are the tuples ints?
- Yes
- Will all tuples have the first element less than the second?
- Yes
- Is there an upper bound on the input range?
- No
- Is the output a list of tuples?
- Yes
- Is the output a new array?
- Yes
- Can we assume the inputs are valid?
- No, check for None
- Can we assume this fits memory?
- Yes
Test Cases¶
* None input -> TypeError * [] - [] * [(2, 3), (7, 9)] -> [(2, 3), (7, 9)] * [(2, 3), (3, 5), (7, 9), (8, 10)] -> [(2, 5), (7, 10)] * [(2, 3), (3, 5), (7, 9), (8, 10), (1, 11)] -> [(1, 11)] * [(2, 3), (3, 8), (7, 9), (8, 10)] -> [(2, 10)]
Algorithm¶
Refer to the Solution Notebook. If you are stuck and need a hint, the solution notebook's algorithm discussion might be a good place to start.
Code¶
In [ ]:
class Solution(object):
def merge_ranges(self, array):
# TODO: Implement me
pass
Unit Test¶
The following unit test is expected to fail until you solve the challenge.
In [ ]:
# %load test_merge_ranges.py
import unittest
class TestMergeRanges(unittest.TestCase):
def test_merge_ranges(self):
solution = Solution()
self.assertRaises(TypeError, solution.merge_ranges, None)
self.assertEqual(solution.merge_ranges([]), [])
array = [(2, 3), (7, 9)]
expected = [(2, 3), (7, 9)]
self.assertEqual(solution.merge_ranges(array), expected)
array = [(2, 3), (3, 5), (7, 9), (8, 10)]
expected = [(2, 5), (7, 10)]
self.assertEqual(solution.merge_ranges(array), expected)
array = [(2, 3), (3, 5), (7, 9), (8, 10), (1, 11)]
expected = [(1, 11)]
self.assertEqual(solution.merge_ranges(array), expected)
print('Success: test_merge_ranges')
def main():
test = TestMergeRanges()
test.test_merge_ranges()
if __name__ == '__main__':
main()
Solution Notebook¶
Review the Solution Notebook for a discussion on algorithms and code solutions.