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I am creating a view from code behind. The view contains Title column for which I would like to be a link to open the list item and have a drop-down menu.

I know that this is done by setting <FieldRef Name='Title' ListItemMenu='TRUE' />, but how can I achieve the same thing from code behind?

Here is the code for creating a view: 

private SPView CreateView(SPList list, string title, string[] columnDisplayNames)
{
    StringCollection columns;
    string columnInternalName;
    SPViewCollection views;
    SPView view;

    columns = new StringCollection();
    foreach (string columnDisplayName in columnDisplayNames)
    {
        columnInternalName = this.GetListColumnInternalName(list, columnDisplayName);
        columns.Add(columnInternalName);
    }

    views = list.Views;
    view = views.Add(title, columns, string.Empty, 30, true, true);
    view.Update();

    for (int i = views.Count - 2; i >= 0; i--)
    {
        views.Delete(views[i].ID);
    }

    return view;
}

Note: The accepted answer in this question is false, as the Title field that has ListItemMenu is LinkTitle (internal name) and using that column throws an exception.

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  • Did you get it working? Commented Jun 15, 2016 at 12:35

1 Answer 1

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You can use below mention code. It is used to show Context menu in other column apart from Title Column in SharePoint List.

SPList list = site.RootWeb.Lists["Tasks"]; //Change the list name here
SPField field = list.Fields["Priority"]; //Change the column name here
field.ListItemMenu = true;
field.ListItemMenuAllowed = SPField.ListItemMenuState.Required;
field.Update();
list.Update();

You can replace the column name with your column name.

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