Skip to main content
added 1 character in body
Source Link
rwong
  • 17.2k
  • 3
  • 38
  • 82

Just an outline of thought.

To me, it seems bruteforce and streetsmart will beat any theoretical approach.

Example #1

If N contains a factor of 2 up to multiplicities K, then you can deduce that the lowest digits of X will have to contain at least K consecutive zeroes, because only consecutive zeroes in the lowest digits can provide factors of 2. And so on. Doesn't seem to involve any theories.

Example #2

Another streetsmart is the divisibility by 9 of decimal numbers judged by the sum of decimal digits. (More precisely it's the property of the modulo by 9. Divisibility refers to modulo beinggiving zero. Divisibility by 3 is a simple corollary derived from the modulo by 9.) Note that by using "modulo", it is not only applicable to multiples of 9 - you can apply it to any numbers, say 13, by filtering the candidates of X suchwith the requirement that mod(X_candidate, 9) == mod(13, 9) == 4. The requirement is necessary but not sufficient, but it helps cutting down the number of cases needed by the bruteforce.

Just an outline of thought.

To me, it seems bruteforce and streetsmart will beat any theoretical approach.

Example #1

If N contains a factor of 2 up to multiplicities K, then you can deduce that the lowest digits of X will have to contain at least K consecutive zeroes, because only consecutive zeroes in the lowest digits can provide factors of 2. And so on. Doesn't seem to involve any theories.

Example #2

Another streetsmart is the divisibility by 9 of decimal numbers judged by the sum of decimal digits. (More precisely it's the property of the modulo by 9. Divisibility refers to modulo being zero. Divisibility by 3 is a simple corollary derived from the modulo by 9.) Note that by using "modulo", it is not only applicable to multiples of 9 - you can apply it to any numbers, say 13, by filtering the candidates of X such that mod(X_candidate, 9) == mod(13, 9) == 4

Just an outline of thought.

To me, it seems bruteforce and streetsmart will beat any theoretical approach.

Example #1

If N contains a factor of 2 up to multiplicities K, then you can deduce that the lowest digits of X will have to contain at least K consecutive zeroes, because only consecutive zeroes in the lowest digits can provide factors of 2. And so on. Doesn't seem to involve any theories.

Example #2

Another streetsmart is the divisibility by 9 of decimal numbers judged by the sum of decimal digits. (More precisely it's the property of the modulo by 9. Divisibility refers to modulo giving zero. Divisibility by 3 is a simple corollary derived from the modulo by 9.) Note that by using "modulo", it is apply it to any numbers, say 13, by filtering the candidates of X with the requirement that mod(X_candidate, 9) == mod(13, 9) == 4. The requirement is necessary but not sufficient, but it helps cutting down the number of cases needed by the bruteforce.

Source Link
rwong
  • 17.2k
  • 3
  • 38
  • 82

Just an outline of thought.

To me, it seems bruteforce and streetsmart will beat any theoretical approach.

Example #1

If N contains a factor of 2 up to multiplicities K, then you can deduce that the lowest digits of X will have to contain at least K consecutive zeroes, because only consecutive zeroes in the lowest digits can provide factors of 2. And so on. Doesn't seem to involve any theories.

Example #2

Another streetsmart is the divisibility by 9 of decimal numbers judged by the sum of decimal digits. (More precisely it's the property of the modulo by 9. Divisibility refers to modulo being zero. Divisibility by 3 is a simple corollary derived from the modulo by 9.) Note that by using "modulo", it is not only applicable to multiples of 9 - you can apply it to any numbers, say 13, by filtering the candidates of X such that mod(X_candidate, 9) == mod(13, 9) == 4