std::chrono::year_month_weekday_last::operator+=, std::chrono::year_month_weekday_last::operator-=

< cpp‎ | chrono‎ | year month weekday last

constexpr std::chrono::year_month_weekday_last& operator+=( const std::chrono::years& dy ) const noexcept;	(1)	(since C++20)
constexpr std::chrono::year_month_weekday_last& operator+=( const std::chrono::months& dm ) const noexcept;	(2)	(since C++20)
constexpr std::chrono::year_month_weekday_last& operator-=( const std::chrono::years& dy ) const noexcept;	(3)	(since C++20)
constexpr std::chrono::year_month_weekday_last& operator-=( const std::chrono::months& dm ) const noexcept;	(4)	(since C++20)

Modifies the time point *this represents by the duration dy or dm.

1) Equivalent to *this = *this + dy;

2) Equivalent to *this = *this + dm;

3) Equivalent to *this = *this - dy;

4) Equivalent to *this = *this - dm;

For durations that are convertible to both std::chrono::years and std::chrono::months, the years overloads (1,3) are preferred if the call would otherwise be ambiguous.

Example

#include <iostream>
#include <chrono>
using namespace std::chrono;
 
int main()
{
    std::cout << std::boolalpha;
 
    auto ymwdl {August/Tuesday[last]/2022};
    ymwdl += months(2);
    std::cout << (year_month_day{ymwdl} == October/25/2022) << ' ';
    ymwdl -= years(1); 
    std::cout << (year_month_day{ymwdl} == October/26/2021) << '\n';
}

Output:

true true

std::chrono::year_month_weekday_last::operator+=, std::chrono::year_month_weekday_last::operator-=

Example

See also