std::complex<T>::real
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primary template complex<T>
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| (1) | ||
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T real() const;
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(until C++14) | |
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constexpr T real() const;
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(since C++14) | |
| (2) | ||
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void real( T value );
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(until C++20) | |
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constexpr void real( T value );
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(since C++20) | |
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specialization complex<float>
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| (1) | ||
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float real() const;
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(until C++11) | |
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constexpr float real() const;
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(since C++11) | |
| (2) | ||
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void real( float value );
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(until C++20) | |
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constexpr void real( float value );
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(since C++20) | |
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specialization complex<double>
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| (1) | ||
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double real() const;
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(until C++11) | |
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constexpr double real() const;
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(since C++11) | |
| (2) | ||
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void real( double value );
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(until C++20) | |
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constexpr void real( double value );
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(since C++20) | |
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specialization complex<long double>
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| (1) | ||
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long double real() const;
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(until C++11) | |
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constexpr long double real() const;
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(since C++11) | |
| (2) | ||
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void real( long double value );
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(until C++20) | |
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constexpr void real( long double value );
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(since C++20) | |
Accesses the real part of the complex number.
1) Returns the real part.
2) Sets the real part to
value.Parameters
| value | - | the value to set the real part to |
Return value
1) The real part.
2) (none)
Notes
In C++11, overload (1) in complex specializations used to be specified without const qualifier. However, in C++11, a constexpr specifier used in a non-static member function implies const, and thus the behavior is as if const is specified.
See also
| returns the real component (function template) |
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| accesses the imaginary part of the complex number (public member function) |