std::is_pointer_interconvertible_base_of

If Derived is unambiguously derived from Base and every Derived object is pointer-interconvertible with its Base subobject, or if both are the same non-union class (in both cases ignoring cv-qualification), provides the member constant value equal to true. Otherwise value is false.

If both Base and Derived are non-union class types, and they are not the same type (ignoring cv-qualification), Derived shall be a complete type; otherwise the behavior is undefined.

The behavior of a program that adds specializations for is_pointer_interconvertible_base_of or is_pointer_interconvertible_base_of_v is undefined.

Helper variable template

Notes

std::is_pointer_interconvertible_base_of_v<T, U> may be true even if T is a private or protected base class of U.

Let

• U be a complete object type,
• T be a complete object type with cv-qulification not less than U,
• u be any valid lvalue of U,

reinterpret_cast<T&>(u) always has well-defined result if std::is_pointer_interconvertible_base_of_v<T, U> is true.

If T and U are not the same type (ignoring cv-qualification) and T is a pointer-interconvertible base class of U, then both std::is_standard_layout_v<T> and std::is_standard_layout_v<U> are true.

If T is an empty class type, then all base classes of T (if any) are pointer-interconvertible base class of T.

If T is an non-empty standard layout class type, then all non-empty base classes of T (if any) are pointer-interconvertible base class of T, some empty base classes (if any) might also be pointer-interconvertible base class in this case.

Example

#include <iostream>
#include <type_traits>
 
struct Foo {};
 
struct Bar {};
 
class Baz : Foo, public Bar {
    int x;
};
 
class NonStdLayout : public Baz {
    int y;
};
 
int main() 
{
    std::cout << std::boolalpha
        << std::is_pointer_interconvertible_base_of_v<Bar, Baz> << '\n'
        << std::is_pointer_interconvertible_base_of_v<Foo, Baz> << '\n'
        << std::is_pointer_interconvertible_base_of_v<Baz, NonStdLayout> << '\n'
        << std::is_pointer_interconvertible_base_of_v<NonStdLayout, NonStdLayout> << '\n';
}

true
true
false
true

See also