std::is_unsigned

If T is an integral type, provides the member constant value equal to true if T(0) < T(-1): this results in true for the unsigned integer types and the type bool and in false for the signed integer types and the floating-point types.

For any other type, value is false.

The behavior of a program that adds specializations for is_unsigned or is_unsigned_v (since C++17) is undefined.

Template parameters

Helper variable template

Possible implementation

namespace detail {
template<typename T,bool = std::is_arithmetic<T>::value>
struct is_unsigned : std::integral_constant<bool, T(0) < T(-1)> {};
 
template<typename T>
struct is_unsigned<T,false> : std::false_type {};
} // namespace detail
 
template<typename T>
struct is_unsigned : detail::is_unsigned<T>::type {};

Example

#include <iostream>
#include <type_traits>
 
class A {};
enum B : unsigned {};
enum class C : unsigned {};
 
int main() 
{
    std::cout << std::boolalpha;
    std::cout << std::is_unsigned<A>::value << '\n';
    std::cout << std::is_unsigned<float>::value << '\n';
    std::cout << std::is_unsigned<signed int>::value << '\n';
    std::cout << std::is_unsigned<unsigned int>::value << '\n';
    std::cout << std::is_unsigned<B>::value << '\n';
    std::cout << std::is_unsigned<C>::value << '\n';
}

false
false
false
true
false
false

See also