I am trying to remove all spaces/tabs/newlines in python 2.7 on Linux.
I wrote this, that should do the job:
myString="I want to Remove all white \t spaces, new lines \n and tabs \t"
myString = myString.strip(' \n\t')
print myString
output:
I want to Remove all white spaces, new lines
and tabs
It seems like a simple thing to do, yet I am missing here something. Should I be importing something?
Use str.split([sep[, maxsplit]]) with no sep or sep=None:
From docs:
If
sepis not specified or isNone, a different splitting algorithm is applied: runs of consecutive whitespace are regarded as a single separator, and the result will contain no empty strings at the start or end if the string has leading or trailing whitespace.
Demo:
>>> myString.split()
['I', 'want', 'to', 'Remove', 'all', 'white', 'spaces,', 'new', 'lines', 'and', 'tabs']
Use str.join on the returned list to get this output:
>>> ' '.join(myString.split())
'I want to Remove all white spaces, new lines and tabs'
If you want to remove multiple whitespace items and replace them with single spaces, the easiest way is with a regexp like this:
>>> import re
>>> myString="I want to Remove all white \t spaces, new lines \n and tabs \t"
>>> re.sub('\s+',' ',myString)
'I want to Remove all white spaces, new lines and tabs '
You can then remove the trailing space with .strip() if you want to.
Use the re library
import re
myString = "I want to Remove all white \t spaces, new lines \n and tabs \t"
myString = re.sub(r"[\n\t\s]*", "", myString)
print myString
Output:
IwanttoRemoveallwhitespaces,newlinesandtabs
This will only remove the tab, newlines, spaces and nothing else.
import re
myString = "I want to Remove all white \t spaces, new lines \n and tabs \t"
output = re.sub(r"[\n\t\s]*", "", myString)
OUTPUT:
IwantoRemoveallwhiespaces,newlinesandtabs
Good day!
import re
mystr = "I want to Remove all white \t spaces, new lines \n and tabs \t"
print re.sub(r"\W", "", mystr)
Output : IwanttoRemoveallwhitespacesnewlinesandtabs
The above solutions suggesting the use of regex aren't ideal because this is such a small task and regex requires more resource overhead than the simplicity of the task justifies.
Here's what I do:
myString = myString.replace(' ', '').replace('\t', '').replace('\n', '')
or if you had a bunch of things to remove such that a single line solution would be gratuitously long:
removal_list = [' ', '\t', '\n']
for s in removal_list:
myString = myString.replace(s, '')
How about a one-liner using a list comprehension within join?
>>> foobar = "aaa bbb\t\t\tccc\nddd"
>>> print(foobar)
aaa bbb ccc
ddd
>>> print(''.join([c for c in foobar if c not in [' ', '\t', '\n']]))
aaabbbcccddd
Since there is not anything else that was more intricate, I wanted to share this as it helped me out.
This is what I originally used:
import requests
import re
url = 'https://stackoverflow.com/questions/10711116/strip-spaces-tabs-newlines-python' # noqa
headers = {'user-agent': 'my-app/0.0.1'}
r = requests.get(url, headers=headers)
print("{}".format(r.content))
Undesired Result:
b'<!DOCTYPE html>\r\n\r\n\r\n <html itemscope itemtype="http://schema.org/QAPage" class="html__responsive">\r\n\r\n <head>\r\n\r\n <title>string - Strip spaces/tabs/newlines - python - Stack Overflow</title>\r\n <link
This is what I changed it to:
import requests
import re
url = 'https://stackoverflow.com/questions/10711116/strip-spaces-tabs-newlines-python' # noqa
headers = {'user-agent': 'my-app/0.0.1'}
r = requests.get(url, headers=headers)
regex = r'\s+'
print("CNT: {}".format(re.sub(regex, " ", r.content.decode('utf-8'))))
Desired Result:
<!DOCTYPE html> <html itemscope itemtype="http://schema.org/QAPage" class="html__responsive"> <head> <title>string - Strip spaces/tabs/newlines - python - Stack Overflow</title>
The precise regex that @MattH had mentioned, was what worked for me in fitting it into my code. Thanks!
Note: This is python3
