Items in JSON object are out of order using "json.dumps"?

As others have mentioned the underlying dict is unordered. However there are OrderedDict objects in python. ( They're built in in recent pythons, or you can use this: http://code.activestate.com/recipes/576693/ ).

I believe that newer pythons json implementations correctly handle the built in OrderedDicts, but I'm not sure (and I don't have easy access to test).

Old pythons simplejson implementations dont handle the OrderedDict objects nicely .. and convert them to regular dicts before outputting them.. but you can overcome this by doing the following:

class OrderedJsonEncoder( simplejson.JSONEncoder ):
   def encode(self,o):
      if isinstance(o,OrderedDict.OrderedDict):
         return "{" + ",".join( [ self.encode(k)+":"+self.encode(v) for (k,v) in o.iteritems() ] ) + "}"
      else:
         return simplejson.JSONEncoder.encode(self, o)

now using this we get:

>>> import OrderedDict
>>> unordered={"id":123,"name":"a_name","timezone":"tz"}
>>> ordered = OrderedDict.OrderedDict( [("id",123), ("name","a_name"), ("timezone","tz")] )
>>> e = OrderedJsonEncoder()
>>> print e.encode( unordered )
{"timezone": "tz", "id": 123, "name": "a_name"}
>>> print e.encode( ordered )
{"id":123,"name":"a_name","timezone":"tz"}

Which is pretty much as desired.

Another alternative would be to specialise the encoder to directly use your row class, and then you'd not need any intermediate dict or UnorderedDict.

hey i know it is so late for this answer but add sort_keys and assign false to it as follows :

json.dumps({'****': ***},sort_keys=False)

this worked for me

The order of a dictionary doesn't have any relationship to the order it was defined in. This is true of all dictionaries, not just those turned into JSON.

>>> {"b": 1, "a": 2}
{'a': 2, 'b': 1}

Indeed, the dictionary was turned "upside down" before it even reached json.dumps:

>>> {"id":1,"name":"David","timezone":3}
{'timezone': 3, 'id': 1, 'name': 'David'}

json.dump() will preserve the ordder of your dictionary. Open the file in a text editor and you will see. It will preserve the order regardless of whether you send it an OrderedDict.

But json.load() will lose the order of the saved object unless you tell it to load into an OrderedDict(), which is done with the object_pairs_hook parameter as J.F.Sebastian instructed above.

It would otherwise lose the order because under usual operation, it loads the saved dictionary object into a regular dict and a regular dict does not preserve the oder of the items it is given.

Provided you're using Python 3.7+ , it does preserve the order.

Prior to Python 3.7, dict was not guaranteed to be ordered, so inputs and outputs were typically scrambled unless collections.OrderedDict was specifically requested. Starting with Python 3.7, the regular dict became order preserving, so it is no longer necessary to specify collections.OrderedDict for JSON generation and parsing.

https://docs.python.org/3/library/json.html#json.dump

Based on Michael Anderson's answer but also works when you pass in an array

class OrderedJsonEncoder(simplejson.JSONEncoder):
    def encode(self, o, first=True):
        if type(o) == list and first:
            return '[' + ",".join([self.encode(val, first=False) for val in o]) + ']'
        if type(o) == OrderedDict:
            return "{" + ",".join(
                [self.encode(k, first=False) + ":" + self.encode(v) for (k, v) in o.iteritems()]
            ) + "}"
        else:
            return simplejson.JSONEncoder.encode(self, o)