The following statement doesn't work in Java, but works in C:
char c[] = "abcdefghijklmn";
What's wrong?
Does the char array can only be initialized as following?
char c[] = {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n'};
5 Answers
You could use
char c[] = "abcdefghijklmn".toCharArray();
if you don't mind creating an unnecessary String.
Unlike in C, Strings are objects, and not just arrays of characters.
That said, it's quite rare to use char arrays directly. Are you sure you don't want a String instead?
2 Comments
Victor S
The primitive types are not enough to represent all data types comparing to C?
JB Nizet
All objects are built from basic data types, String included. But the point of using objects is that they offer a much richer API than basic data types. Want to remove whitespace from the beginning and end, use
trim(). Want to search for a substring, use indexOf(). Want to split on separators, use split(). Want to make sure accesses to the String from concurrent threads is safe: no problem: String is thread-safe and immutable, unlike a char array. Why use a char array and reimplement all this by yourself?You can initialize it from a String:
char[] c = "abcdefghijklmn".toCharArray();
However, if what you need is a string, you should simply use a string:
String s = "abcdefghijklmn";
Comments
If you don't want to use String toCharArray(), then yes, a char array must be initialized like any other array- char[] c = new char[] {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n'};
Comments
The literal "abcdefghijklmn" is a String object in Java. You can quickly convert this into a char array by using the String toCharArray() method.
Try this:
char[] c = "abcdefghijklmn".toCharArray();
Comments
Try this:
String a = "abcdefghijklmn";
char[] c = a.toCharArray();
char[]