Using named url patterns throws error in Django 1.4

Question

I am using named url-patterns in my Django app, but it is failing and I don't know why. I have followed the docs but my app errors out when it reads urls.py.

This works:

urls.py

from django.conf.urls import patterns
from www.apps.newsletter.models import Newsletter
from www.apps.newsletter.views import index, detail

urlpatterns = patterns('',
    (r'^vol(?P<q_vol>\d+)/no(?P<q_no>\d+)/(?P<q_slug>[^.*]+)/$', detail),
    (r'^vol(?P<q_vol>\d+)/no(?P<q_no>\d+)/$', index),
    (r'^vol(?P<q_vol>\d+)/$', index),
    (r'^$', index),
)

But this fails:

urls.py

from django.conf.urls import patterns
from www.apps.newsletter.models import Newsletter
from www.apps.newsletter.views import index, detail

urlpatterns = patterns('',
    (r'^vol(?P<q_vol>\d+)/no(?P<q_no>\d+)/(?P<q_slug>[^.*]+)/$', detail, name='newsletter-detail'),
    (r'^vol(?P<q_vol>\d+)/no(?P<q_no>\d+)/$', index),
    (r'^vol(?P<q_vol>\d+)/$', index),
    (r'^$', index),
)

I want to use named url patterns (so I can use {% url %} in my template), but Django doesn't seem to want to play nice. Any ideas? All I am doing is adding the arg name="" and it causes the error:

SyntaxError at /newsletter/

invalid syntax (urls.py, line 6)

This urls.py is referenced by the parent urls.py:

urlpatterns = patterns('',
    url(r'^grappelli/', include('grappelli.urls')),
    url(r'^admin/', include(admin.site.urls)),
    url(r'^software/', include('www.apps.software.urls')),
    url(r'^newsletter/', include('www.apps.newsletter.urls')),
)

I am using Django version 1.4. TIA.

@IgnacioVazquez-Abrams: Thanks - you are correct. Should I delete this question then? — tatlar
– tatlar, Commented Aug 21, 2012 at 22:01

Community · Accepted Answer · 2020-06-20 09:12:55Z

3

You need to use the url function to make use of the name parameter:

url(r'^vol(?P<q_vol>\d+)/no(?P<q_no>\d+)/(?P<q_slug>[^.*]+)/$', detail, name='newsletter-detail'),

In other words, there is a difference between using a tuple and the url function.

Btw, you don't need to have named url patterns to make use of the url template tag, you can just use the view's path instead, i.e. {% url "app.views.myview" %}

edited Jun 20, 2020 at 9:12

CommunityBot

11 silver badge

answered Aug 21, 2012 at 21:47

Timmy O'Mahony

54.1k19 gold badges160 silver badges182 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

tatlar Over a year ago

Thanks. Thought it must be something simple like that. Must remember to RTFM more thoroughly....

Collectives™ on Stack Overflow

Using named url patterns throws error in Django 1.4

1 Answer 1

1 Comment

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Linked

Related