I need to find all two-char sumbols in UNICODE, except underscore. Current solutin is:
pattern = re.compile(ur'(?:\s*)(\w{2})(?:\s*)', re.UNICODE | re.MULTILINE | re.DOTALL)
print pattern.findall('a b c ab cd vs sd a a_ _r')
['ab', 'cd', 'vs', 'sd', 'a_', '_r']
I need to exclude underscore _ from regex, so a_ AND _r are not found. The problem is, my characters can be in any language. So i can't use regex like this: [^a-zA-Z]. For example, in russian:
print pattern.findall(u'ф_')
Exclude anything that's a non-word char AND _
[^\W_]
instead of
\w
Your best bet would be to use the new regex module instead. One of it's features is that it can remove characters from a character set:
import regex as re
pattern = re.compile(ur'(?:\s*)([\w--_]{2})(?:\s*)', re.UNICODE | re.MULTILINE | re.DOTALL)
The [\w--_] syntax creates a character set that is the same as \w with the underscore character removed from the matching characters.
This seems to work for me:
a="Exclude_from_search"
re.search("(\w[^_]+)", a).group(0)
'Exclude'
