How to get error/notification integer arithmetic overflow in Java?

Question

Let's have a simple code as below

public class Sandbox {

    public static void run(String[] args) {
        int i = Integer.MAX_VALUE;
        int j = i+1;
        System.out.println(i);
        System.out.println(j);
    }
}

This will print output

2147483647

-2147483648

Value at j is overlowed without any notice to me when the code is executed.

I use Netbeans IDE to run this code.

Is it possible to configure the system to notify us when such arithmetic overflow occurs?

You have to use if-else for this, to check for overflow manually.. Also,you have to create your own exeption. — Rohit Jain
– Rohit Jain, Commented Oct 14, 2012 at 7:45

halex · Accepted Answer · 2012-10-14 07:48:13Z

4

See the last sentence in the Java Language Specification (Chapter 15.18.2. Additive Operators (+ and -) for Numeric Types) :

Despite the fact that overflow, underflow, or loss of information may occur, evaluation of a numeric additive operator never throws a runtime exception.

For a lengthy article on this problem and the presentation of a tool for workaround see the article Signalling Integer Overflows in Java.

answered Oct 14, 2012 at 7:48

halex

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Comments

techraf · Accepted Answer · 2016-04-29 11:25:14Z

1

In the Math API since Java 8, you can use:

Math.addExact(i, 1);

It will throw an ArithmeticException if the result overflows an int.

edited Apr 29, 2016 at 11:25

techraf

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answered Apr 29, 2016 at 10:40

user2212346

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