parse xml feed using python feedparser

Question

i have this feed which i would like to pull the info out of http://www.boutique-artisans-du-monde.com/rss/catalog/category/cid/6/store_id/1/

from the code i have

try:
   xml = urllib2.urlopen(link_rss)
except urllib2.URLError, e:
   pass
else:
   f = feedparser.parse(xml)
   print len(f.entries)

when i print the len(f.entries) maximum entries i get is 50 what is the correct way to pull all the entries?

Community · Accepted Answer · 2017-05-23 12:27:45Z

2

I think it returns all the entries, maybe that's only what the feed contains. If you want to pull older entries you will have to find the correct feed and pass it to the feedparser RSS is just an XML file stored at the server.

check this answer

edited May 23, 2017 at 12:27

CommunityBot

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answered Nov 11, 2012 at 17:40

iabdalkader

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4 Comments

Kien Truong Over a year ago

Yep, the feed only contains 50 items

iabdalkader Over a year ago

@Dikei I guess this answers your question :)

Kien Truong Over a year ago

It's not my question though :)

iabdalkader Over a year ago

@Dikei sorry, confused you for the OP :)

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