how to call method statically if object and class name is same in java

Question

class SomeClass
{
    static public void someStaticMethod(){};
}

SomeClass SomeClass=new SomeClass();
SomeClass.someStaticMethod();

How to call the static method of any class where object name is same as class name?

Why would you have the class name and object name same on the first place? — Rohit Jain
– Rohit Jain, Commented Jan 28, 2013 at 15:52
prepend the package name to the class. i.e com.mypackage.SomeClass.someStaticMethod(); — munyengm
– munyengm, Commented Jan 28, 2013 at 15:53
Also: the object name should explain why this object exists. If it's just a random someClass then it shouldn't exist anyway. Is it the "target" of something, the "source", the "frobnicator"? Having variable names that are equal to class names (even if they differ in case) is a slight code smell in my opinion. — Joachim Sauer
– Joachim Sauer, Commented Jan 28, 2013 at 15:55

Community · Accepted Answer · 2020-06-20 09:12:55Z

You don't have to do anything - it will work as is (although it makes little sense to use such a confusing code).

How ambiguous names are handled is specified in the JLS #6.5.2. In particular:

If the AmbiguousName is a simple name, consisting of a single Identifier:

If the Identifier appears within the scope (§6.3) of a local variable declaration (§14.4) or parameter declaration (§8.4.1, §8.8.1, §14.20) or field declaration (§8.3) with that name, then the AmbiguousName is reclassified as an ExpressionName.

[...]

Otherwise, if a type of that name is declared in the compilation unit (§7.3) containing the Identifier, either by a single-type-import declaration (§7.5.1), or by a type-import-on-demand declaration (§7.5.2), or by a single-static-import declaration (§7.5.3), or by a static-import-on-demand declaration (§7.5.4), then the AmbiguousName is reclassified as a TypeName.

So in your case, SomeClass will be the variable you declared one line above, which has priority over types.

Rob · Accepted Answer · 2013-01-28 15:52:37Z

3

The variable name should not be capitalized, hence you would have:

SomeClass.someStaticMethod();

for the static one and:

someClass.someNonStaticMethod();

for the non-static versions.

answered Jan 28, 2013 at 15:52

Rob

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Comments

Orabîg · Accepted Answer · 2013-01-28 15:51:53Z

0

Do not start instance names with capital letter !

You should write :

SomeClass someClass=new SomeClass();

or better yet :

SomeClass someObject=new SomeClass();

If you follow these very common rules, you won't have this issue. (I'm trying to guess where this '-1' comes from !!!)

answered Jan 28, 2013 at 15:51

Orabîg

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2 Comments

varuog Over a year ago

yes, i know. but i am curious if there is any other way around or not as stating both class and object same does not show any compilation error.

Orabîg Over a year ago

Well you should try by youself and tell us the answers. However, this is only possible if you keep this very bad coding habits... (the -1 just disappeared ;) never mind)

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