You could match each line to a regular expression with a capturing group, like so:
for l in page:
m = re.match("Website is: (.*)")
if m:
print m.groups()[0]
This would both check if each line matched the pattern, and extract the link from it.
A few pitfalls:
This assumes that the "Website is" expression is always at the start of the line. If it's not, you could use re.search.
This assumes there is exactly one space between the colon and the website. If that's not true, you could change the expression to something like Website is:\s+(http.*).
The specifics will depend on the page you are trying to parse.