Python MongoDB : 'Cursor' object has no attribute 'name'

Question

Just started with mongo db .

context = {}
if request.method == 'POST':
    context['name']  = request.POST['name']
    context['username']  = request.POST['username']
    context['mobile']  = request.POST['mobile']
    get = db.messages.find( { 'name' : request.POST['name'] } )
    if get is not None:
        print get.name

I have two records in my database .

> db.messages.find()
{ "_id" : ObjectId("513f2cf1ae4cb53c1374b4f6"), "username" : "[email protected]", "mobile" : "78978555", "name" : "rohit" }
{ "_id" : ObjectId("513f2cfeae4cb53c1374b4f7"), "username" : "[email protected]", "mobile" : "8528522", "name" : "Rohti" }

when i am posting the form with name rohit . I am getting the above error .

Please tell me what might i am doing wrong here .

I know i am doing wrong query in mongo db .Please help me to get back on track .

what is get when you print it?

Hoopdady
– Hoopdady

2013-03-12 14:09:44 +00:00
Commented Mar 12, 2013 at 14:09 — Hoopdady
– Hoopdady, Commented Mar 12, 2013 at 14:09

glormph · Accepted Answer · 2013-03-12 14:09:44Z

8

get returns as a cursor in pymongo.

try:

for record in get:
    print record['name']

Also, get is not a good name for a variable.

answered Mar 12, 2013 at 14:09

glormph

1,0147 silver badges14 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

masterofdestiny Over a year ago

thanks it is working for me .But what if i want to check only for single record. Should i do the same for FindOne also ?

glormph Over a year ago

find_one returns a dict, so then you don't have to iterate but can directly address it: x = find_one({'name': your_name}) then print x['name']

masterofdestiny Over a year ago

last thing what if there is no matching query it returns None or what?

glormph Over a year ago

try it. find will return an empty iterator. find_one will return None

Jacopofar · Accepted Answer · 2013-03-12 14:27:58Z

1

You have to iterate with the cursor:

for element in get:
    print(element.name)

now you are accessing the cursor, which is just a generator of elements and doesn't contain the name directly. See here for a complete explanation.

edited Mar 12, 2013 at 14:27

answered Mar 12, 2013 at 14:10

Jacopofar

3,5072 gold badges21 silver badges29 bronze badges

1 Comment

masterofdestiny Over a year ago

Above query will also work print(element.name) instead of print(get.name)

Collectives™ on Stack Overflow

Python MongoDB : 'Cursor' object has no attribute 'name'

2 Answers 2

4 Comments

1 Comment

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

4 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Linked

Related