Memory size of Java 32-bit system int[] arrays

Question

In Java, on a 32 bit OS, I store 5736 int[] arrays containing 54759118 ints. If each int primitive takes 4 bytes, then I will get minimum 54759118 * 4 = 219036472 bytes ~ 220 megabytes. Since I have 5736 references to int[] objects, what will be an overhead of storing those references?

Andremoniy · Accepted Answer · 2013-04-16 09:03:31Z

2

Each 32-bit pointer in Java allocates ~4 bytes. Hence, it will be 5736 * 4 = 22944 bytes

answered Apr 16, 2013 at 9:03

Andremoniy

35.2k25 gold badges143 silver badges259 bronze badges

Sign up to request clarification or add additional context in comments.

5 Comments

Vincent van der Weele Over a year ago

There are only 5736 references

Andremoniy Over a year ago

@Heuster ups :)) Thank you very much, its my inattention.

Sophie Sperner Over a year ago

Thank you, so this will be an overhead size, 23 megabytes? Is something spent on storing say length of array, or only ints as contents and array references are stored?

Andremoniy Over a year ago

@SophieSperner 4 bytes per an array reference. It doesn't depend on array's length. And it is only 22 kilobytes, not megabytes :)

Sophie Sperner Over a year ago

Just a comment aside: by the link at the end they say that int[1024] takes 4112 bytes. If you use our logic: 1024 * 4 + 4 (ref) = 4100 < 4112 consequently 12 bytes are stored for something else. Link: vanillajava.blogspot.ie/2011/07/…

Collectives™ on Stack Overflow

Memory size of Java 32-bit system int[] arrays

1 Answer 1

5 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

5 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related