Last newbie question for today. There is a hash:
h = {a: 1, b: 2, c: 3}
How to implement convert_to_arr(h) method with such output:
convert_to_arr(h)
# ["Key: 'a', Value: '1'",
# "Key: 'b', Value: '2'",
# "Key: 'c', Value: '3'"]
Thanks!
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3 Answers
{a: 1, b: 2, c: 3}.map { |key, value| "Key: '#{key}', Value: '#{value}'" }
=> ["Key: 'a', Value: '1'", "Key: 'b', Value: '2'", "Key: 'c', Value: '3'"]
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h = {a: 1, b: 2, c: 3}
h.map{|k,v| "key: '#{k}' ,val: '#{v}'"}
# => ["key: 'a' ,val: '1'", "key: 'b' ,val: '2'", "key: 'c' ,val: '3'"]
1 Comment
Serg Ra6n
Priti, thanks for all prompt and correct answers and good night! (in my country is 00:31, 21-07-2013)
You could always implement a struct:
struct keyItem
{
char key[30];
int value;
}
And then do something like this:
keyItem h[3] =
{
{ "a", 1 },
{ "b", 2 },
{ "c", 3 }
}
Your function like this:
void print_keys(keyItem[] k, int size)
{
for (int i = 0; i < size; i++)
{
printf("Key: \"%s\", Value: '%d'\n", k[i].key, k[i].value);
}
}
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