regexp in php str_replace

Question

I want to use a regexp in my str_replace, i suppose the correct solution to this would be to use preg_replace but i don't know how to use that. Anyway i want to turn src= into the character a if it matches src= or if it has any spaces in between src and =. Normally to just turn src= it'd be:

$string = str_replace('src=', 'a', $string);

But the problem is that wouldn't work when there are space(s) between src and =. This is why i need to use a regexp. Thanks for any help.

That's why php.net/manual/en/function.preg-replace.php exists :) For future reference, always remember to Google first, a query for regexp in php str_replace will take you right there. — Pekka
– Pekka, Commented Aug 20, 2013 at 21:48

federicot · Accepted Answer · 2013-08-20 22:00:43Z

1

$string = preg_replace('/src\s*=/i', 'a', $string);

What that RegEx means is "match src followed by 0 or more spaces followed by =".

edited Aug 20, 2013 at 22:00

answered Aug 20, 2013 at 21:52

federicot

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4 Comments

dognose Over a year ago

if there is no whitspace, this fails. use * instead of +. Second, = is no special char, so no escaping required.

federicot Over a year ago

@dognose Corrected it.

Bob Sm Over a year ago

@Campari Nice, just one more tweak. How can i make src case insensitive?

federicot Over a year ago

@BobSm Sure. The i modifier at the end makes the RegEx case insensitive.

dognose · Accepted Answer · 2013-08-20 21:49:51Z

0

preg_replace just works as str_replace:

$new_string = preg_replace($pattern, $replacement, $old_string);

The pattern in your case would be "@src\s*=@i" (\s* covers zero to infinite whitespaces, @ is just one out of different possible delimeters the pattern requires, i (after the last delimiter) makes the pattern case insensitive.)

answered Aug 20, 2013 at 21:49

dognose

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Comments

ninty9notout · Accepted Answer · 2013-08-20 21:56:23Z

0

Use preg_replace and the following pattern:

src(?:\s+)?=

Split this up:

src obviously finds the "src" part
(?:\s+)? finds 0 or more space(s)
= to finish it off, finds the "="

So altogether, it would be:

$new_string = preg_replace("/src(?:\s+)?=/i", 'a', $string);

Hope this helps!

answered Aug 20, 2013 at 21:56

ninty9notout

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