mt_rand in function causing parse error

Question

I am working from some code I found online but modified the function a little bit.
My function is

function generate_random_password($length=10)
{      
    $letters = 'bcdfghjklmnprstvwxzaeiou';

    $result = '';
    for($i=0; $i<$length; $i++)
    {
        $result =. ($i%2) ? $letters[mt_rand(19, 23)] : $letters[mt_rand(0, 18)];
    }

    return $result;
}

And I am echoing the random password like this

echo generate_random_password($_GET['length']);

The moment I added the mt_rand() in the $result line it stopped working. Any help would be appreciated. Thanks.

When you give errors, don't paraphrase. Don't say "It's a parse error." Cut & paste the entire message so that we can see exactly what it says. — Andy Lester
– Andy Lester, Commented Aug 21, 2013 at 4:13

vee · Accepted Answer · 2013-08-21 03:50:32Z

4

The parse error is because of =.. It should be .= as follows:

$result .= ($i%2) ? $letters[mt_rand(19, 23)] : $letters[mt_rand(0, 18)];

answered Aug 21, 2013 at 3:50

vee

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Comments

Padmanathan J · Accepted Answer · 2013-08-21 04:32:59Z

1

change .= instead of =.

$result .= ($i%2) ? $letters[mt_rand(19, 23)] : $letters[mt_rand(0, 18)];

answered Aug 21, 2013 at 4:32

Padmanathan J

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