Passing a value in inline PHP to a javascript variable

Question

var testvr = <?php echo 5;?>;

When this is used in my javascript I get an "Unexpected token <" error on the line. I've seen countless examples of people setting a javascript variable like this so I'm a bit confused. I've seen some do it as

var testvr = "<?php echo 5;?>";

But that passes the code as a string to the variable. I'm really just looking for a way to simply set a javascript variable to something from php, nothing fancy at all it would just be a number such as 5.

Show some more code. And of course you have to call it from PHP script. — Elon Than
– Elon Than, Commented Sep 16, 2013 at 10:59
pass the code as a string to the variable and then parse it as int in javascript — Voonic
– Voonic, Commented Sep 16, 2013 at 11:00
There is no problem with the code provided there must some different error. you can share more code — Anup Singh
– Anup Singh, Commented Sep 16, 2013 at 11:07
The problem was that it wasn't a .php file, been so long since I've used inline PHP I forgot that bit. Thanks for the quick responses! — Cains
– Cains, Commented Sep 16, 2013 at 11:14

Quentin · Accepted Answer · 2013-09-16 14:23:08Z

2

When this is used in my javascript I get an "Unexpected token <" error on the line.

This means that you aren't passing the file through a PHP parser before delivering it to the browser.

Presumably you are placing the PHP in a .js file. Either rename that file to .php or configure your server to process your .js files with PHP.

Don't forget that PHP will default to sending Content-Type: text/html so make sure you include header("Content-Type: application/javascript");.

answered Sep 16, 2013 at 14:23

Quentin

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Flash Thunder · Accepted Answer · 2013-09-16 11:01:50Z

1

It is safe to use an object:

<?php
   $vars = array('var1' => 'val1', 'var2' => 'val2', 'intvar' => 55);
?>

<script>
   var myvars = <?php json_encode($vars);?>
   console.log(myvars.var1);
   console.log(myvars.var2);
   console.log(myvars.intvar);
</script>

The above will keep numbers as numbers and all unsafe characters will get escaped.

answered Sep 16, 2013 at 11:01

Flash Thunder

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