assign a variable from a file and compare with integer in Unix

Question

i have only one character to read from a file in UNIX. When i assign the file to a variable and compare with integer it gives integer error.

count.txt contains numeric character. Below is the code

#!/usr/local/bin/bash
_count=/apps/count.txt
_value=20
if [ _value -ge _count ] then
echo "Value is greater"
fi
exit 0

you're not reading a file. It should be something like _count=$(cat /apps/count.txt) — keltar
– keltar, Commented Sep 17, 2013 at 3:00

PaulV · Accepted Answer · 2013-09-17 03:13:56Z

1

_count=$( cat /apps/count.txt )
_value=20
if [ $_value -ge $_count ]; then
    echo "Value is greater"
fi
exit 0

You can access the value in count.txt with "cat" and assign it to the variable. You also forgot to add a ";" after the if statement.

answered Sep 17, 2013 at 3:13

PaulV

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1 Comment

Thanks Script is running without semicolon

Aleks-Daniel Jakimenko-A. · Accepted Answer · 2013-09-17 14:00:45Z

1

You don't even have to use cat! Also you can use (( )) for arithmetical operations:

count=$( < count.txt)
value=20

if (( value >= count )); then
    echo "Value is greater"
fi
exit 0

answered Sep 17, 2013 at 14:00

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