Adding the last element to string after array

Question

My storage string gives me all the digits in want besides the last, I know its because the last digit has nothing to compare to the right. Can I add the last digit to the end of my string somehow,

    for(int i = 0;i < othercontent.length -1 ;i++ )
    {
        if(othercontent[i] != othercontent[i + 1])
        {
            storage = storage + othercontent[i]; 

        }
    }

I have sorted and now I am getting rid of all the duplicates in the array — user2780490
– user2780490, Commented Sep 18, 2013 at 11:27
the whole program is huge so its kinda hard to give an input output example but say AABBBCCC will go in AB will come out I want ABC — user2780490
– user2780490, Commented Sep 18, 2013 at 11:28
I am only trying to get rid of duplicates not the last element and I cant use the API methods — user2780490
– user2780490, Commented Sep 18, 2013 at 11:30

Rafi Kamal · Accepted Answer · 2013-09-18 11:31:30Z

1

for(int i = 0; i < othercontent.length ;i++ )
{
    if(i == 0 || othercontent[i] != othercontent[i - 1])
    {
        storage = storage + othercontent[i]; 
    }
}

answered Sep 18, 2013 at 11:31

Rafi Kamal

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1 Comment

Krishna Sarma Over a year ago

I am little wary to add additional checks inside the loop. Instead, you can push the 0th iteration outside.

Melih Altıntaş · Accepted Answer · 2013-09-18 12:06:54Z

1

if othercontent is String array :

TreeSet<String> set = new TreeSet<>(Arrays.asList(othercontent));
othercontent = set.toArray(new String[0]);
for (String string : othercontent) {
    System.out.println(string);
}

if othercontent is String :

String othercontent = "ZZZZQQWEDDODRAABBNNNNO";
LinkedList<Character> list = new LinkedList<>();
for (Character character : othercontent.toCharArray()) {
    list.add(character);
}
TreeSet<Character> set = new TreeSet<>(list);
StringBuilder builder = new StringBuilder();
for (Character character : set) {
    builder.append(character);
}

System.out.println(builder.toString());

not only sorting , but also removing dublicates are solved with this code

OUTPUT :

ABDENOQRWZ

edited Sep 18, 2013 at 12:06

answered Sep 18, 2013 at 11:41

Melih Altıntaş

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Comments

BackSlash · Accepted Answer · 2013-09-18 11:27:08Z

0

You can check if you reached the last element:

for(int i = 0;i < othercontent.length -1; i++ ) {
    if(othercontent[i] != othercontent[i + 1]) {
        storage = storage + othercontent[i]; 
    }
    //only gets executed if the last iteration is reached
    if(i==othercontent.length-2) {
        storage = storage + othercontent[i+1];
    }
}

Or, instead of using a condition, just write this after your loop:

storage = storage + othercontent[othercontent.length-1];

answered Sep 18, 2013 at 11:27

BackSlash

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1 Comment

Krishna Sarma Over a year ago

You don't need to add additional condition inside the loop, instead you can just add the last char outside the loop (with some additional checks if needed). something like storage = storage + othercontent[othercontent.length-1];

Siva · Accepted Answer · 2013-09-18 11:30:36Z

0

You can add the last digit to your string outside of for loop as it doesn't require to check any condition

 for(int i = 0;i < othercontent.length -1; i++ ) {
    if(othercontent[i] != othercontent[i + 1]) {
        storage = storage + othercontent[i]; 
    }

}

 storage = storage + othercontent[othercontent.length - 1];

answered Sep 18, 2013 at 11:30

Siva

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Comments

Kishore · Accepted Answer · 2013-09-18 11:32:12Z

0

for(int i = 0; i < othercontent.length -1 ; ++i )    {
    if(othercontent[i] != othercontent[i + 1]) {
        storage = storage + othercontent[i];
    }
}
if(othercontent.length>0){
    storage = storage + othercontent[othercontent.length-1];
}

answered Sep 18, 2013 at 11:32

Kishore

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Comments

Krishna Sarma · Accepted Answer · 2013-09-18 11:36:27Z

0

If you are checking for the duplicates, you should do something like this outside the loop.

if(othercontent.length>0 && storage[storage.length-1] ! = othercontent[othercontent.length-1])
{
    storage = storage+othercontent[othercontent.length-1];
}

answered Sep 18, 2013 at 11:36

Krishna Sarma

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