Template Interface Implementation Class C++ error

Question

I'm having a small issue with template inheritance.

If I create an interface class with a template:

template<typename Data>   
class InterfaceClass {
   private:
   public:
      virtual Data* foo() = 0; //some function that returns our template type
}

Then I create an implementation of this:

template<typename MoData>
class Implementation : public InterfaceClass<MoData> {
   private:
   public:
      MoData* foo() { MoData* ptr = NULL; return ptr; } //some implementation
}

I seem to have trouble with this working in my compiler. Is this not legal?

Pierre Fourgeaud · Accepted Answer · 2013-09-19 06:17:02Z

3

template<typedef Data>

is not correct.

You should use

template<class Data>

or

template<typename Data>

answered Sep 19, 2013 at 6:17

Pierre Fourgeaud

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4 Comments

Lee Jacobs Over a year ago

yeah, whoops I have it is typename in my code... not typedef.... my bad... long day lol

Pierre Fourgeaud Over a year ago

@LeeJacobs If you add the missing ; it compiles fine with me : ideone.com/8PeBDB.

Pierre Fourgeaud Over a year ago

@LeeJacobs Sorry I was playing with it, try again :)

Lee Jacobs Over a year ago

ok I tested it out on my system I know what I was doing wrong. Thanks man.

The Quantum Physicist · Accepted Answer · 2013-09-19 06:17:10Z

1

template <typedef Data>

is wrong, use

template <typename Data>

answered Sep 19, 2013 at 6:17

The Quantum Physicist

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Comments

shofee · Accepted Answer · 2013-09-19 06:25:58Z

0

Please add semicolon at the end of class declaration.

template<typename Data>   
class InterfaceClass {
   private:
   public:
      virtual Data* foo() = 0; //some function that returns our template type
};

answered Sep 19, 2013 at 6:25

shofee

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