Access an element in a list of lists in python

Question

I am new to python and am trying to access a single specific element in a list of lists. I have tried:

line_list[2][0]

this one isn't right as its a tuple and the list only accepts integers.

line_list[(2, 0)]

line_list[2, 0]

This is probably really obvious but I just can't see it.

def rpd_truncate(map_ref):

    #Munipulate string in order to get the reference value
    with open (map_ref, "r") as reference:
        line_list = []
        for line in reference:
            word_list = []
            word_list.append(line[:-1].split("\t\t"))
            line_list.append(word_list)

    print line_list[2][0]

I get the exact same as if I used line_list[2]:

['Page_0', '0x00000000', '0x002DF8CD']

The first one is correct - why do you think it doesn't work? What happened when you tried it? Also post what line_list contains so we can help you. — Brionius
– Brionius, Commented Oct 11, 2013 at 10:27
you have to show your code. line_list[2][0] should work for list of lists, like [[1, 2, 3], [4, 5, 6]]. Are you sure you have list of lists? Are you sure you didn't get 'index out of range' exception? — roman
– roman, Commented Oct 11, 2013 at 10:29
@Brionius is correct. Multidimensional array access works this way. Try a = [4,5,6] ; b = [a,7,8]; print b[0][2] — user2363448
– user2363448, Commented Oct 11, 2013 at 10:31
this one isn't right as its a tuple and the list only accepts integers. A list can contain any Python object, unless you are using some sort of custom list. Reading elements from a tuple is the same as form a list. I wonder, are you trying to write new items to a list in this way? Show us your code and the error message you get. — cdarke
– cdarke, Commented Oct 11, 2013 at 10:35
First one will work fine on python lists and second, third will work fine on numpy arrays. — Ashwini Chaudhary
– Ashwini Chaudhary, Commented Oct 11, 2013 at 10:36

suhailvs · Accepted Answer · 2013-10-11 10:50:50Z

1

actually split will return a list more over you don't require word_list variable

for line in reference:       
    line_list.append(line[:-1].split("\t\t"))
print line_list[2][0]

answered Oct 11, 2013 at 10:50

suhailvs

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