PHP array printing 'array' instead of values. [duplicate]

Question

I am using this code but can't figure out what's wrong with it.

if (!empty($_POST)) {
    foreach ($_POST as $key => $value) {
        if (get_magic_quotes_gpc()) 
            $value=stripslashes($value);
        if ($key=='extras') {       
            if (is_array($_POST['extras'])) {
                print "<tr><td><code>$key</code></td><td>";
                foreach ($_POST['extras'] as $value) {
                print "<i>$value</i><br />";
                }
                print "</td></tr>";
                } 
            else {
                print "<tr><td><code>$key</code></td><td><i>$value</i></td></tr>\n";
                }
            } 
        else {
            print "<tr><td><code>$key</code></td><td><i>$value</i></td></tr>\n";
        }
    } // end foreach
}

It prints prgm 'array' in table instead of values inside array.

@u_mulder I think it's not going inside if (is_array($_POST['extras'])) — user2769614
– user2769614, Commented Oct 13, 2013 at 17:32
it's going inside else, I'm not able to figure it out, please help — user2769614
– user2769614, Commented Oct 13, 2013 at 20:16

sloanelybutsurely · Accepted Answer · 2013-10-13 16:56:38Z

2

I feel like using print_r() would be at least a way to gain some insight into the structure of the array.

answered Oct 13, 2013 at 16:56

sloanelybutsurely

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5 Comments

user2769614 Over a year ago

I think it's not going inside if (is_array($_POST['extras']))

H2ONOCK Over a year ago

print_r is definitely your friend here!

user2769614 Over a year ago

this is not working, please help!!

sloanelybutsurely Over a year ago

@user2876449 : could you maybe post how you are attempting to use print_r()? I would first just call print_r($_POST) to see the structure of the POST array.

user2769614 Over a year ago

this worked when i changed if (is_array($_POST['extras'])) to if (is_array($value))

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