Compiler says Java code is invalid

Question

I am working on a Java code:

import java.util.Scanner;

public class main
{
    static Scanner console = new Scanner (System.in);
    public static void main (String aurgs[]) {

        System.out.print("Which function would you like to vist? L for Lottery, R for Random Math");
        char lotto = 'l';
        char rdm = 'b';

        if (console.nextChar() = lotto) /**error is here*/ {
            lottery();
        }
    }
    public static void lottery (String aurgs[]) {
        String announ = "Your lottery numbers for today are: ";
        System.out.print(announ);
        int [] numbers = {15, 68, 25, 66};
        double lucky = 50.2;
        for (int i: numbers )
            System.out.print(i + "\n");

        String announ2 = "Your lucky number is: ";
        System.out.println(announ2 + lucky);
        }
}

When I compile it, BlueJ says:

cannot find symbol - method nextChar()

I do not understand what is wrong.

You can't just make up methods and expect them to work. No, programming is an exercise in precision, and compilers are unforgiving. You'll want to learn to use the Java API and use it a lot. — Hovercraft Full Of Eels
– Hovercraft Full Of Eels, Commented Oct 17, 2013 at 3:37
It may be because you are using the assignment operator = instead of the comparison operator == in your if clause, but @Hovercraft is probably right. — David Fleeman
– David Fleeman, Commented Oct 17, 2013 at 3:38
Being a bit more specific: There is no Scanner#nextChar() method. (But there are a number of similar questions, which makes me thing some professor or class notes started with an incorrect assertion ..) — user2864740
– user2864740, Commented Oct 17, 2013 at 3:39
Use some IDEs such as Eclipse, they will tell you what methods available to you. — Chowdappa
– Chowdappa, Commented Oct 17, 2013 at 3:40
See also: stackoverflow.com/questions/18746185/… , stackoverflow.com/questions/19340543/… — user2864740
– user2864740, Commented Oct 17, 2013 at 3:41

hexacyanide · Accepted Answer · 2013-10-17 03:37:45Z

3

The Scanner class has no nextChar() method. The methods available are listed here, none of which are nextChar(). You can instead use next() and read a single character as a string.

answered Oct 17, 2013 at 3:37

hexacyanide

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Comments

Pshemo · Accepted Answer · 2013-10-17 03:44:27Z

2

I do not understand what is wrong.

It is simple. Scanner doesn't have nextChar() method.

If you want to read characters with Scanner you can change its delimiter to empty string ""

console.useDelimiter("");

and use next() method.

Also you should add one more = in

if (console.nextChar() = lotto)

if you want to compare chars (single = is used for assigning values).

edited Oct 17, 2013 at 3:44

answered Oct 17, 2013 at 3:38

Pshemo

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Comments

sandymatt · Accepted Answer · 2013-10-17 03:38:56Z

1

In order to get a char from a Scanner you need to use next(), which returns a String. Then just get the first char from that.

char x = console.next().charAt(0);

answered Oct 17, 2013 at 3:38

sandymatt

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2 Comments

Brandon Nguyen Over a year ago

I feel so dumb now. Thanks.

sandymatt Over a year ago

No worries -- happens to everybody

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