I have a PHP script where I want to show its progess. From this super question and perfect answer How to add a progress bar to a shell script? I tried to emulate the behaviour:
shell_exec("echo -ne '###### 30%'\r");
But nothing gets printed to the screen.
My guess is this is because STDOUT not correct, or I have to echo the echo like?
echo shell_exec("echo -ne '###### 30%'\r");
To use this in a php shell script you don't need to execute any shell commands at all. Just echo the output ending with a \r
echo "###### 30%\r";
example script:
<?php
for ($i = 0; $i < 100; $i += 5) {
$bar = str_repeat("#", $i/10);
echo "$i% $bar \r";
sleep(1);
}
echo "\n";
?>
$i <= 100 or else the script will end in 95% i guess
-ne from the system's echo. I should have tried.. =)-ne does. The bash echo command always adds \n at the end. -n ommits the trailing newline. -e enables the interpretion of backslash escapes. Without it the \r would have no effect. The PHP echo needs none of these options.There is a good example for a progress bar in PHP command line interface: http://brian.moonspot.net/php-progress-bar
It is directly done in PHP without system calls.
