How to manually get an instance of a dependency in angular js?

Question

I have an object reportsService, which for each call it make's, it initialises a new object called serviceCall. Each method needs to instantiate it's own instance of serviceCall.

Is using $injector.get() the correct way to do this?

app.factory('reportsService', ['$injector', function ($injector) {
    var o = {};
    o.getServiceCall = function () {
        return $injector.get('serviceCall');
    };
    o.getOriginCompositionData = function (ajaxOptions) {
        ajaxOptions.url = '/test/SpiderRequestOriginComposition';
        o.getServiceCall().initialize(ajaxOptions);
    };
    o.getExeuctionTimeData = function (ajaxOptions) {
        ajaxOptions.url = '/test/SpiderRequestExeuctionTime';
        o.getServiceCall().initialize(ajaxOptions);
    };
    o.getCacheCompositionData = function (ajaxOptions) {
        ajaxOptions.url = '/test/SpiderRequestCacheComposition';
        o.getServiceCall().initialize(ajaxOptions);
    };
    return o;
}]);

jpsimons · Accepted Answer · 2013-12-02 05:05:16Z

2

You could simply inject a second parameter called "serviceCall" after (or I guess instead of) "$injector" and use that. It'll be captured in closure and useable from any of your "o" function.

answered Dec 2, 2013 at 5:05

jpsimons

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5 Comments

williamsandonz Over a year ago

I wanted to do this, but if I include it as a parameter in my factory declaration, I only get one instance of it right? Because I need a different instance for each method...

jpsimons Over a year ago

Even with $injector.get, it's the same instance. In Angular (unlike Guice for example that has different "scopes") anything injected is a singleton.

jpsimons Over a year ago

It's actually kind of confusing in my opinion -- whether you use a factor or service, it's only ever instantiated once. Makes me wonder why "factory" even exists.

williamsandonz Over a year ago

Thanks for the help, what I don't get now, is how you create an object which isn't a singleton, but still doesn't pollute the global namespace lol

williamsandonz Over a year ago

Have created a new question for this, refer: stackoverflow.com/questions/20321915/…

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