BASH - problems assigning variable using counter in variable name

Question

I have a groups of files in a folder. Each group is identified by characters 3-6 in the file name. I want to read in all the files of the group, count how many files there are, and then assign the file name to a variable made up of some letters and the counter. e.g. FILENAME$COUNTER. My code is almost working but there seems to be a problem with assigning the counter to the variable name.

I get this error for the line with code FILE$COUNTER=$i

line 12: FILE1=5_lib1ln1_BWA_ddrot_testonl_pe12.bam: command not found

This is exactly what I wanted for the variable name and assignment, but its saying command not found. I'm not sure why there is a command not found.

#!/bin/bash
## All files from the same group have the same LIB
LIB='lib1'
COUNTER=0

for i in 5_*.bam
do
    SAMPLIB=`echo $i | cut -c 3-6`
    if [ "$LIB" = "$SAMPLIB" ]; then
            let COUNTER++
            FILE$COUNTER=$i
    fi
NUMFILES=$COUNTER
done

Community · Accepted Answer · 2017-05-23 11:49:44Z

1

Replace

FILE$COUNTER=$i

with

eval FILE$COUNTER=$i

See eval command in Bash and its typical uses for more information.

edited May 23, 2017 at 11:49

CommunityBot

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answered Dec 7, 2013 at 1:17

Adam Liss

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