Python string replace

Question

I have this code:

    ALPHABET1 = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
    key = "TES"
    ALPHABET2 = key + ALPHABET1
    count_result = ALPHABET2.count("T")
    if (count_result > 1):
    ALPHABET3 = ALPHABET1.replace("T","")
    ALPHABET2 = key + ALPHABET3         
    print(ALPHABET2)

I want to be able to put the keyword at the start of the alphabet string to create a new string without repeating the letters in the keyword. I'm having some problems doing this though. I need the keyword to work for all letters as it will be user input in my program. Any suggestions?

string is a "tuple" of values. You could make a set of letters, than convert back to string(draw back for simple implementation is that order it's changed). But I think a simple parser-loop for eache letter, in a list comprehension-it may be the right solution for you. If it sound strange, tell me and I expand this in an answer — cox
– cox, Commented Jan 24, 2014 at 19:42

jonrsharpe · Accepted Answer · 2014-01-24 19:43:41Z

1

Two things:

You don't need to make the alphabet yourself, import string and use string.ascii_uppercase; and
You can use a for loop to work through the characters in your key.

To illustrate the latter:

for c in key:
    alphabet = alphabet.replace(c, "")

Better yet, a list is mutable, so you can do:

alpha = [c for c in string.ascii_uppercase if c not in key]
alpha.extend(set(key))

answered Jan 24, 2014 at 19:43

jonrsharpe

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2 Comments

jonrsharpe Over a year ago

Neither of the approaches I outline needs to know the length of the key. A for loop works through however many characters there are.

ubuntuaskdanidani Over a year ago

yeah.. i figured it out just after posting :))

aschmid00 · Accepted Answer · 2014-01-24 19:50:30Z

0

its easy and clean to do this with a regex

import re

ALPHABET1   = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
key         = "TES"
newalphabet = key.upper() + re.sub(r'%s'%'|'.join(key.upper()), '', ALPHABET1)

or with a list comprehension like @jonrsharpe suggested

answered Jan 24, 2014 at 19:50

aschmid00

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