Copy an element of struct array to another struct of same types

Question

If there is a structure:

struct Student // Student structure to store student's records
{
int rollno; // student rollno
string name; // student name
string address; // address
int pno; // phone number
};

and int main() contains

int main()
{
Student *s;
s= new Student [10];
}

Then how can we assign a struct to a different struct of same types?

void arrange()
{
Student *p= new Student;
//    int temp;
    for (int i=0; i<10; i++)
    {
        for (int j=0; j<10; j++)
        {
            if (i != j)
            {
                if (s[i].rollno > s[j].rollno)
                {
                    p = s[i];
                    s[i] = s[j];
                    s[j] = p;
                }
             }
        }
    }

You can't use bold format in markup formatted code. Use *p = s[i];and s[j] = *p; to make assignments to/from p. — πάντα ῥεῖ
– πάντα ῥεῖ, Commented Feb 8, 2014 at 9:15
thanks .... it's the first time i am using ... thats why ... — Shaan
– Shaan, Commented Feb 8, 2014 at 9:18
Please provide a SSCCE. Your code has a variable in the scope of main() and you try to use it in arrange(). — harper
– harper, Commented Feb 8, 2014 at 9:18
it doesn't gives an error but void arrange() also doesnt executes :-/ *p = s[i]; s[i] = s[j]; s[j] = *p; — Shaan
– Shaan, Commented Feb 8, 2014 at 9:21

juanchopanza · Accepted Answer · 2014-02-08 09:18:27Z

1

Than how can we assign a struct to a different struct of same types

Just copy construct it:

int main()
{
    Student s[10]; // array of 10 students
    Student student = s[5]; // copy of 6th element of array
}

You are over-complicating things with all those pointers.

answered Feb 8, 2014 at 9:18

juanchopanza

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Comments

hivert · Accepted Answer · 2014-02-08 09:19:39Z

0

If you declare p as a pointer to a student then the struct is accessed by *p. So you should write:

*p = s[i];
s[i] = s[j];
s[j] = *p;

However, I don't think having a pointer is of any use here. Just write

Student p;

answered Feb 8, 2014 at 9:19

hivert

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