In Python how do I convert:
list01 = [ ['a', 'b', 'c'], ['i', 'j', 'k'], ['x', 'y', 'z'] ]
into
list02 = [ 'abc', 'ijk', 'xyz']
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4 Answers
Using map:
map(''.join, list01)
Or with a list comprehension:
[''.join(x) for x in list01]
Both output:
['abc', 'ijk', 'xyz']
Note that in Python 3, map returns a map object instead of a list. If you do need a list, you can wrap it in list(map(...)), but at that point a list comprehension is more clear.
Comments
Use str.join and a list comprehension:
>>> list01 = [ ['a', 'b', 'c'], ['i', 'j', 'k'], ['x', 'y', 'z'] ]
>>> [''.join(x) for x in list01]
['abc', 'ijk', 'xyz']
>>>
Comments
>>> map(''.join, list01)
['abc', 'ijk', 'xyz']
Comments
You can use join to implode the elements in a string and then append, if you don't want to use map.
# Your list
someList = [ ['a', 'b', 'c'], ['i', 'j', 'k'], ['x', 'y', 'z'] ]
implodeList = []
# make an iteration with for in
for item in someList:
implodeList.append(''.join(item))
# printing your new list
print(implodeList)
['abc', 'ijk', 'xyz']
