Let's suppose the following table:
X VALUE
1 2
1 3
2 NULL
2 4
I want a result set grouped by X with the sum of VALUE, but only if all the rows related to each X value are not null.
Using the same example, the result must be:
X SUM(VALUE)
1 5
As you can see, X=2 is not selected due to the (2, NULL) tuple.
I want, whenever this is possible, without using subqueries.
Thank you very much!
You can achieve that with:
SELECT
x,
SUM(value)
FROM
t
GROUP BY
x
HAVING
COUNT(value)=COUNT(*)
This will work following way: group values in normal way, but then compare entire count (so * points to that) with column count (which won't include NULL-s). If they are not equal, then there are NULL's and value shouldn't be included.
Another way is this. It may or may not be faster:
SELECT X, IF(SUM(VALUE is NULL), NULL, SUM(VALUE)) as value
FROM table_name
group by X
having not(null <=> value);
Also, with this method, if you remove the having clause you get all rows, but with null values for the summed columns with nulls which you then could conditionally do something else with in your script.
This whould work:
SELECT SUM(value) FROM test WHERE value IS NOT NULL GROUP BY X
