I have an URL address like: http://myfile.com/File1/beauty.png
I have to remove http://site address/ from main string
That mean result should be File1/beauty.png
Note: site address might be anything(e.g some.com, some.org)
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BUild Regex and extract the content you want. use sites like this to build the regex. txt2re.com/…Mani– Mani2014-04-03 12:30:09 +00:00Commented Apr 3, 2014 at 12:30
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4 Answers
See here: http://docs.oracle.com/javase/tutorial/networking/urls/urlInfo.html
Just create a URL object out of your string and use URL.getPath() like this:
String s = new URL("http://myfile.com/File1/beauty.png").getPath();
If you don't need the slash at the beginning, you can remove it via s.substring(1, s.length());
Edit, according to comment:
If you are not allowed to use URL, this would be your best bet: Extract main domain name from a given url
See the accepted answer. Basically you have to get a TLD list, find the domain and substract everything till the domain names' end.
2 Comments
Surendra Jnawali
I have to use only pure string methods substring or split see tags
Surendra Jnawali
Your answer is also useful: But Url exactly need url format( should have http://)
If, as you say, you only want to use the standard String methods then this should do it.
public static String getPath(String url){
if(url.contains("://")){
url = url.substring(url.indexOf("://")+3);
url = url.substring(url.indexOf("/") + 1);
} else {
url = url.substring(url.indexOf("/")+1);
}
return url;
}
If the url contains :// then we know that the string you are looking for will come after the third /. Otherwise, it should come after the first. If we do the following;
System.out.println(getPath("http://myfile.com/File1/beauty.png"));
System.out.println(getPath("https://myfile.com/File1/beauty.png"));
System.out.println(getPath("www1.myfile.com/File1/beauty.png"));
System.out.println(getPath("myfile.co.uk/File1/beauty.png"));;
The output is;
File1/beauty.png
File1/beauty.png
File1/beauty.png
File1/beauty.png
7 Comments
INK
I like your answer. Maybe you should extend getPath() to check, if it is prefixed by "://" and filter that out before extracting the string. This would be more failsafe - and you do not even need a loop to extract the string. Never the less - I'll give you my upvote :)
Rudi Kershaw
@INK - That's a good idea. I might test it with a series of URLs and see how that goes. If all works out I'll update the answer.
INK
@Rudi Great :) You should consider removing the loop and replace it with: url = url.substring(url.indexOf("://")+3); (haven't tested it, but it should work). Just a performance thing though :)
Rudi Kershaw
@INK - That would retrieve the site domain as well, which I don't think they want.
INK
Well, today is really not my day :D What about this one: url = url.substring(url.indexOf("://")+3); url = url.substring(url.indexOf("/") + 1); ? I just forgot the second line of code.
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You can use the below approach to fetch the required data.
String url = "http://myfile.org/File1/beauty.png";
URL u = new URL(url);
String[] arr = url.split(u.getAuthority());
System.out.println(arr[1]);
Output - /File1/beauty.png
Comments
String s = "http://www.freegreatpicture.com/files/146/26189-abstract-color-background.jpg";
s = s.substring(s.indexOf("/", str.indexOf("/") + 1));
1 Comment
Surendra Jnawali
your result: /www.freegreatpicture.com/files/146/26189-abstract-color-background.jpg