How to create xhtml query strings with Scala?

Question

How do I create an x(ht)ml-Node containing a href-attribute including a query string without the &s being escaped automatically or runtime error?

val text = Text("?key=val&key2=val2")

will be escaped and

val node = <a href="link?key=val&key2=val2">link</a>

throws (in Scala 2.7.5):

java.lang.AssertionError

The node will be used with the Lift bind() helper method, preferably with AttrBindParam().

huynhjl · Accepted Answer · 2010-02-24 15:03:24Z

5

try:

val text = scala.xml.Unparsed("link?key=val&key2=val2")
val node = <a href={text}>link</a>

But may be you really mean:

val node = <a href="link?key=val&amp;key2=val2">link</a>

answered Feb 24, 2010 at 15:03

huynhjl

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Comments

Daniel C. Sobral · Accepted Answer · 2010-02-24 18:07:41Z

1

The following will escape the ampersand:

val node = <a href={"link?key=val&key2=val2"}>link</a>

Which, arguably, is what you really need.

answered Feb 24, 2010 at 18:07

Daniel C. Sobral

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