Is it possible to use a regular expression with the php function array_key_exists()?
For example:
$exp = "my regex";
array_key_exists($exp, $array);
Thank you!
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2 Answers
You can extract the array keys using array_keys() and then use preg_grep() on that array:
function preg_array_key_exists($pattern, $array) {
$keys = array_keys($array);
return (int) preg_grep($pattern,$keys);
}
.
$arr = array("abc"=>12,"dec"=>34,"fgh"=>56);
var_dump(preg_array_key_exists('/c$/',$arr)); // check if a key ends in 'c'.
var_dump(preg_array_key_exists('/x$/',$arr)); // check if a key ends in 'x'.
function preg_array_key_exists($pattern, $array) {
// extract the keys.
$keys = array_keys($array);
// convert the preg_grep() returned array to int..and return.
// the ret value of preg_grep() will be an array of values
// that match the pattern.
return (int) preg_grep($pattern,$keys);
}
Output:
$php a.php
int(1)
int(0)
1 Comment
zerkms
instead of flipping you can use array_keys()
No, I'm afraid not. You can iterate the array keys and perform matches on those:
$keys = array_keys($array);
foreach ($keys as $key)
if (preg_match($exp, $key) == 1)
return $array[$key];
2 Comments
zerkms
or just if(preg_match(...)) in the case of multiple result occurencies.
Andrew Moore
@zerkms:
preg_match() only matches the first occurrence of the pattern. Therefore it can only return 0 or 1. Please see php.net/preg_match