Finding Substring from a String

Try this,

String text = "Test: Testid #123123 - Updated";
int startIndex = text.indexOf('#'); //Finds the first occurrence of '#' 
int endIndex = text.indexOf(' ',startIndex); //Finds the first occurrence of space starting from position of # 
String subString = text.substring(startIndex+1, endIndex);
System.out.println(subString);

Or try to use regex

If your example is really as simple as the one you give, then you will not need to use regular expressions. However, if your real input is more complex, then the regular expression will be less onerous than trying to split the string in a clever way.

import java.util.regex.*;


public class Foo{
    public static void main(String[] args) {
        String original =  "Test: Testid #123123 - Updated";
            Pattern mypattern = Pattern.compile("#([0-9]*) ");
        Matcher matcher = mypattern.matcher(original);
        while (matcher.find()) {
            System.out.println(matcher.group(1));
        }
    }
}

Just split it with # then split the result with - you will get the correct result.

Have you tried int indexOf(int ch, int fromIndex) ? You can search for the next space from the given index.

http://docs.oracle.com/javase/tutorial/java/data/manipstrings.html

this might be helpful..

String temp="Test: Testid #123123 - Updated";
 int _first=temp.indexOf("#");
 int _last= temp.indexOf(" ", _first);
String result=temp.substring(_first, _last);

You can use following code to get the value between '#' and space.

String str = "Test: Testid #123123 - Updated";
str = str.substring(str.indexOf('#')+1, str.indexOf(' ', str.indexOf("#")+1)+1);