How to echo the cURL result in PHP?

Question

Here is a URL→ https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=snoopy&rsz=1

and this is my php code

<?php
    $url = "https://ajax.googleapis.com/ajax/services/search/images?"."v=1.0&q=snoopy";

    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    $body = curl_exec($ch);
    curl_close($ch);

    $json = json_decode($body);
?>

I wanna echo all of the image urls from its result
(For example: http://img2.wikia.nocookie.net/__cb20110331075248/peanuts/images/6/62/Snoopy.gif )

But I have no idea how to echo them.
Hope someone could help me, thanks!

if the link comes as a response then just echo $body :-?

Ares Draguna
– Ares Draguna

2014-11-13 13:28:09 +00:00
Commented Nov 13, 2014 at 13:28 — Ares Draguna
– Ares Draguna, Commented Nov 13, 2014 at 13:28

brandelizer · Accepted Answer · 2014-11-13 15:41:30Z

2

Maybe like this:

<?php
    $url = "https://ajax.googleapis.com/ajax/services/search/images?" .
   "v=1.0&q=barack%20obama&userip=INSERT-USER-IP";

   // sendRequest
   // note how referer is set manually
   $ch = curl_init();
   curl_setopt($ch, CURLOPT_URL, $url);
   curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
   curl_setopt($ch, CURLOPT_REFERER, 'http://example.com');
   $body = curl_exec($ch);
   curl_close($ch);

   // now, process the JSON string
    $pics = json_decode($body);
    $ret='';
    if($pics){
       foreach($pics->responseData->results as $pic)
          $ret .= $pic->url.'<br>';
    }
    echo $ret;
?>

edited Nov 13, 2014 at 15:41

answered Nov 13, 2014 at 13:31

brandelizer

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17 Comments

Ares Draguna Over a year ago

Fatal error: Cannot use object of type stdClass as array on line ... this is what I get after using your code ;)

brandelizer Over a year ago

Why -1? i dont know what the api gives you back.

Ares Draguna Over a year ago

You would if you would actually access the URL that the OP provided ;)

Ares Draguna Over a year ago

just for future reference: {"responseData": {"results":[{"GsearchResultClass":"GimageSearch","width":"608","height":"766"...

Ares Draguna Over a year ago

Much better :) sorry to be such a pain but I really like PHP when it's done right :)

|

Ares Draguna · Accepted Answer · 2014-11-13 13:37:14Z

1

in order to echo the exact result just use:

echo $body; //echoes json string

if you want to echo the exact link, echo like this:

echo $json->responseData->results[0]->url; //echoes http://img2.wikia.nocookie.net/__cb20110331075248/peanuts/images/6/62/Snoopy.gif

or you can foreach() twice (or once...) then echo $res->url directly :) your choise!

edited Nov 13, 2014 at 13:37

answered Nov 13, 2014 at 13:30

Ares Draguna

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7 Comments

Ares Draguna Over a year ago

I updated my answer with the correct format to output that URL. Please take a look now :) and tell me if you need anything more ;)

dingpachan Over a year ago

excuse me. when I echo $body, there is nothing to occur. I also try this code "echo $json->responseData->results[0]->url;" but happened error "Trying to get property of non-object"

Ares Draguna Over a year ago

in your case, $body should contain the json string. Try to var_dump() it and tell me what it outputs ;)

Ares Draguna Over a year ago

this could be because your $body does not contain that exact json string... it might be different... just var_dump() it and then tell me what you get ;)

brandelizer Over a year ago

You have forgotten the CURLOPT_REFERER look at my answer i have edited it

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