Error in arrays output compared to input

Question

I have the code below, where the user has to input 5 values in an array, and print out the same.

package Arrays;

import java.util.Scanner;

public class Arrays {
    public static void main(String[] args) {
        final int size=5;
        Scanner input = new Scanner(System.in);
        System.out.println("Enter the 5 number you want to be stored in an array");
        int a[] =new int[size];
        for(int i=0;i<a.length;i++){
            a[i]=input.nextInt();
        }           
        displayArray(a);
        sumOfArray();
        productOfArray();
        smallAndLargeOfArray();
        averageOfArray();
    }

    private static void displayArray(int arr[]) {
        for (int i = 0; i < arr.length; i++) {
            System.out.println(arr[i] + ' ');
        }
    }
}

here is my input:

and the output that I'm getting is:

Please let me know where I'm going wrong and how can I fix this.

Remember that a char in java is really just an integer. When you write arr[i] + ' ' you are actually adding 2 numbers, not concatenating 2 strings. — takendarkk
– takendarkk, Commented Nov 26, 2014 at 7:59

Eran · Accepted Answer · 2014-11-26 08:04:24Z

7

Change

System.out.println(arr[i] + ' ');

to

System.out.println(arr[i]);

or

System.out.println(arr[i] + " ");

When you are printing arr[i] + ' ', first the expression is evaluated as the addition of an int and a char (the integral value of the space character, which is 32), and only then the resulting integer is printed. Therefore, all the integers in your array are offset by 32 when printed this way.

edited Nov 26, 2014 at 8:04

answered Nov 26, 2014 at 7:58

Eran

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1 Comment

user3872094 Over a year ago

Thanks for the explaination

khelwood · Accepted Answer · 2014-11-26 08:14:41Z

2

' ' has ascii code 32. When you use arr[i] + ' ' you convert second operand to integer and add to first operand.

edited Nov 26, 2014 at 8:14

khelwood

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answered Nov 26, 2014 at 8:00

Sergii Lagutin

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Comments

Dinal24 · Accepted Answer · 2014-11-26 08:10:47Z

1

In ASCII space has a char value of 32 (decimal) and char is actually an integer value. It gets added to your int value and gives that output.

System.out.println(arr[i]);

and

System.out.println(arr[i]+" ");

will solve the issue.

edited Nov 26, 2014 at 8:10

answered Nov 26, 2014 at 8:05

Dinal24

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