a=1:5
for k=a
if k<3
a=[a k+5];
end
disp(k)
end
When I run this code, I get these results:
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2
3
4
5
k uses only the initial vector when it enters to the loop. I want it to update the values of a and take the new values of a too. Thus, my question is how do I get this result:
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5
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7
ints = 1:5;
i = 0;
while i ~= length(ints)
i = i + 1;
if (i < 3)
ints = [ints i + 5]
end
disp(i)
end
a=1:5
i=1
while i<=length(a)
k=a(i);
if k<3
a=[a k+5];
end
disp(k)
i = i + 1
end
should do the trick. (Disclaimer: I didn't test it)
The index i iterates over a until it is really over.
