I need to put all numeric values stored in a String into an array:
String str = "12,1,222,55";
If I do this, then it will merge all numbers:
str = str.replaceAll("\\D+","");
How to get something like this?:
int[] result = new int[]{12,1,122,55};
First split the string. Then parse each element in String array to new array
String[] s=str.split("\\D+");
int[] intarray=new int[s.length];
for(int i=0;i<s.length;i++){
intarray[i]=Integer.parseInt(s[i]);
}
Just split your input according to one or more non-digit characters and then convert the datatype of each element to integer.
String[] parts = str.split("\\D+");
String[] numbers = str.split(",");
And add number one by one to int[] with Integer.parseInt(numbers[i]);
If you don't know the exact size of the input string, I recommend using ArrayList for this purpose. If you know there will be 4 values then go with an array.
Split str on , and map the elements into integers using Integer#parseInt.
Demo:
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
String str = "12,1,222,55";
int[] array = Arrays.stream(str.split(","))
.mapToInt(Integer::parseInt)
.toArray();
System.out.println(Arrays.toString(array));
}
}
Output:
[12, 1, 222, 55]
Extract the integer strings using the pattern, \d+ (i.e. one or more digits) and map them into integers using Integer#parseInt.
int[] array = Pattern.compile("\\d+")
.matcher(line)
.results()
.map(MatchResult::group)
.mapToInt(Integer::parseInt)
.toArray();
Demo:
import java.util.Arrays;
import java.util.List;
import java.util.regex.MatchResult;
import java.util.regex.Pattern;
public class Main {
public static void main(String[] args) {
String str = "12,1,222,55";
int[] array = Pattern.compile("\\d+")
.matcher(str)
.results()
.map(MatchResult::group)
.mapToInt(Integer::parseInt)
.toArray();
System.out.println(Arrays.toString(array));
}
}
Output:
[12, 1, 222, 55]
,and covert element to int and store an array.