python: using nested lists as arguments

Question

Trying to use the elements of nested lists for the arguments of a function

list = [[ "stringA" , 11, 22], [ "stringB", 33 , 44]]

def func ( 'str' , a , b ):

I know how to call a single element: list[0][1] and func(*list) to use the lists as an argument.

How do I use the individual elements?

Best not to shadow the builtin list with your own variable. I've used lst instead in my answer — John La Rooy
– John La Rooy, Commented Mar 24, 2015 at 4:52

John La Rooy · Accepted Answer · 2015-03-24 04:52:03Z

3

Do you mean?

func(*lst[0])

Often you might loop over the list

for item in lst:
    func(*item)

answered Mar 24, 2015 at 4:52

John La Rooy

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Comments

sumit-sampang-rai · Accepted Answer · 2015-03-24 04:59:43Z

0

You seem to be trying to unzip the values of list. Try this.

list1 = [[ "stringA" , 11, 22], [ "stringB", 33 , 44]]

def func(string, a, b):
    print string, a, b

for i in list1:
    func(*i)

Output:

stringA 11 22
stringB 33 44

answered Mar 24, 2015 at 4:59

sumit-sampang-rai

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