Unable to telnet to Windows using socket module in python

Question

Im using python3.3 version. I have Windows7 machine, I'm trying to write a program using socket module in python. I'm not to able get login prompt if I use socket module.

import socket
host = '10.155.208.33'
port= 23
s= socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((host,port))
data=s.recv(1024)
print(data)
>>> b"\xff\xfd%\xff\xfb\x01\xff\xfb\x03\xff\xfd'\xff\xfd\x1f\xff\xfd\x00\xff\xfb\x00"
s.sendall(b'\xff\xfe\x01\xff\xfd\x03\xff\xfc\x18\xff\xfc\x1f') >>> Im not sure whether this correct IAC client reply 
data =s.recv(1024)
print(data)
>>>b'' <<< server response is empty.

Im not familar with IAC commands. Can somebody point to correct handshake used for communicating between client and server?

I tried using telnetlib module for python3.3, module doesnt works properly on my windows machine.

Thanks, Anand

Have you read the RFCs?

Deer Hunter
– Deer Hunter

2015-04-08 08:23:30 +00:00
Commented Apr 8, 2015 at 8:23 — Deer Hunter
– Deer Hunter, Commented Apr 8, 2015 at 8:23

Robᵩ · Accepted Answer · 2015-04-09 03:50:02Z

2

You may safely respond negatively to each IAC negotiation request. That is, for each IAC-DO, reply IAC-WONT. For each IAC-WILL, reply IAC-DONT.

You may find this code helpful:

def read(s):
    while True:
        data = s.recv(10240)
        for do in re.findall('\xff\xfd.', data): # IAC DO cmd
            s.send('\xff\xfc'+do[2])  # IAC WONT cmd
        for will in re.findall('\xff\xfb.', data): # IAC WILL cmd
            s.send('\xff\xfe'+will[2])  # IAC DONT cmd
        data = re.sub('\xff[\xfb-\xfe].', '', data)
        if data != '':
            return data

answered Apr 9, 2015 at 3:50

Robᵩ

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